3.346 \(\int \frac{\sqrt{b \sec (e+f x)}}{(d \tan (e+f x))^{4/3}} \, dx\)

Optimal. Leaf size=62 \[ -\frac{3 \sqrt [12]{\cos ^2(e+f x)} \sqrt{b \sec (e+f x)} \, _2F_1\left (-\frac{1}{6},\frac{1}{12};\frac{5}{6};\sin ^2(e+f x)\right )}{d f \sqrt [3]{d \tan (e+f x)}} \]

[Out]

(-3*(Cos[e + f*x]^2)^(1/12)*Hypergeometric2F1[-1/6, 1/12, 5/6, Sin[e + f*x]^2]*Sqrt[b*Sec[e + f*x]])/(d*f*(d*T
an[e + f*x])^(1/3))

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Rubi [A]  time = 0.0527477, antiderivative size = 62, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.04, Rules used = {2617} \[ -\frac{3 \sqrt [12]{\cos ^2(e+f x)} \sqrt{b \sec (e+f x)} \, _2F_1\left (-\frac{1}{6},\frac{1}{12};\frac{5}{6};\sin ^2(e+f x)\right )}{d f \sqrt [3]{d \tan (e+f x)}} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[b*Sec[e + f*x]]/(d*Tan[e + f*x])^(4/3),x]

[Out]

(-3*(Cos[e + f*x]^2)^(1/12)*Hypergeometric2F1[-1/6, 1/12, 5/6, Sin[e + f*x]^2]*Sqrt[b*Sec[e + f*x]])/(d*f*(d*T
an[e + f*x])^(1/3))

Rule 2617

Int[((a_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[((a*Sec[e +
f*x])^m*(b*Tan[e + f*x])^(n + 1)*(Cos[e + f*x]^2)^((m + n + 1)/2)*Hypergeometric2F1[(n + 1)/2, (m + n + 1)/2,
(n + 3)/2, Sin[e + f*x]^2])/(b*f*(n + 1)), x] /; FreeQ[{a, b, e, f, m, n}, x] &&  !IntegerQ[(n - 1)/2] &&  !In
tegerQ[m/2]

Rubi steps

\begin{align*} \int \frac{\sqrt{b \sec (e+f x)}}{(d \tan (e+f x))^{4/3}} \, dx &=-\frac{3 \sqrt [12]{\cos ^2(e+f x)} \, _2F_1\left (-\frac{1}{6},\frac{1}{12};\frac{5}{6};\sin ^2(e+f x)\right ) \sqrt{b \sec (e+f x)}}{d f \sqrt [3]{d \tan (e+f x)}}\\ \end{align*}

Mathematica [A]  time = 0.228715, size = 62, normalized size = 1. \[ \frac{2 d \left (-\tan ^2(e+f x)\right )^{7/6} \sqrt{b \sec (e+f x)} \, _2F_1\left (\frac{1}{4},\frac{7}{6};\frac{5}{4};\sec ^2(e+f x)\right )}{f (d \tan (e+f x))^{7/3}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[b*Sec[e + f*x]]/(d*Tan[e + f*x])^(4/3),x]

[Out]

(2*d*Hypergeometric2F1[1/4, 7/6, 5/4, Sec[e + f*x]^2]*Sqrt[b*Sec[e + f*x]]*(-Tan[e + f*x]^2)^(7/6))/(f*(d*Tan[
e + f*x])^(7/3))

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Maple [F]  time = 0.128, size = 0, normalized size = 0. \begin{align*} \int{\sqrt{b\sec \left ( fx+e \right ) } \left ( d\tan \left ( fx+e \right ) \right ) ^{-{\frac{4}{3}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*sec(f*x+e))^(1/2)/(d*tan(f*x+e))^(4/3),x)

[Out]

int((b*sec(f*x+e))^(1/2)/(d*tan(f*x+e))^(4/3),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{b \sec \left (f x + e\right )}}{\left (d \tan \left (f x + e\right )\right )^{\frac{4}{3}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sec(f*x+e))^(1/2)/(d*tan(f*x+e))^(4/3),x, algorithm="maxima")

[Out]

integrate(sqrt(b*sec(f*x + e))/(d*tan(f*x + e))^(4/3), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{b \sec \left (f x + e\right )} \left (d \tan \left (f x + e\right )\right )^{\frac{2}{3}}}{d^{2} \tan \left (f x + e\right )^{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sec(f*x+e))^(1/2)/(d*tan(f*x+e))^(4/3),x, algorithm="fricas")

[Out]

integral(sqrt(b*sec(f*x + e))*(d*tan(f*x + e))^(2/3)/(d^2*tan(f*x + e)^2), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sec(f*x+e))**(1/2)/(d*tan(f*x+e))**(4/3),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{b \sec \left (f x + e\right )}}{\left (d \tan \left (f x + e\right )\right )^{\frac{4}{3}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*sec(f*x+e))^(1/2)/(d*tan(f*x+e))^(4/3),x, algorithm="giac")

[Out]

integrate(sqrt(b*sec(f*x + e))/(d*tan(f*x + e))^(4/3), x)